-11x^2+45x-36=0

Solution for -11x^2+45x-36=0 equation:

-11x^2+45x-36=0

a = -11; b = 45; c = -36;
Δ = b2-4ac
Δ = 452-4·(-11)·(-36)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-21}{2*-11}=\frac{-66}{-22}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+21}{2*-11}=\frac{-24}{-22}
=1+1/11
$